Tough sorry wish I could help u can’t too hard but I think it is equivalent to the other triangle so I think it’s 31? I THINK
The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
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Answer:
Step-by-step explanation:
Used PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
First Power, next Addition
Well if it pumps 4 2/5 per minute that is equal to 4 4/10 in a minute or 4.4 because you multiply the top and bottom of the fraction by two. it’s still the same fraction but it is easy to convert to a decimal now. you could use this fraction but it’s much easier to use decimals. Because the first number is a decimal you should make the second one a decimal too. To do this you need to know that 1/4 of 100 is 25. so now we have these numbers and all you do now is divide 17.25 by 4.4 which could be rounded to 4 because it’s a long decimal
The volume of soup in the cylindrical can is 100.48 inches cube.
<h3>How to find the volume of a cylindrical can?</h3>
We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.
The volume of the soup is the volume of the cylindrical can.
Therefore,
volume of the cylindrical can = πr²h
where
- r = radius of the cylinder
- h = height of the cylinder
Therefore,
h = 8 inches
r = 4 / 2 = 2 inches
volume of the soup in the cylindrical can = πr²h
volume of the soup in the cylindrical can = π × 2² × 8
volume of the soup in the cylindrical can = π × 4 × 8
volume of the soup in the cylindrical can = 32π
Therefore,
volume of the soup in the cylindrical can = 32 × 3.14
volume of the soup in the cylindrical can = 100.48 inches³
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