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3 years ago

J has a whole life policy with a return of premium rider. Which of the following would best describe this rider?

Business

1 answer:

mixas84 [53]3 years ago

4 0

Answer:

The correct answer is:

A term rider on a permanent policy.

Explanation:

A return of premium rider refers to the case when the insured adds some additional clauses to the normal policy for an extra cost. A rider is obtained considering a specific period of time in which the policy would be paid to the beneficiaries in case of death, sickness or disability of the insured person. In case that the insured subject lives more than the pre-established period of time the amount that he paid for the return of premium rider would be given back to him. For example if J pays $50 monthly for a 30 years life term policy and he lives after that period of time, he will receive $18.000 at the end of the contract as a premium return.

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The aicpa's statements on auditing standards can be described as

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The AICPA’s Statements on Auditing Standards is a guideline for auditors. This guideline shows what the minimal standards are in order for an auditor to perform their work correctly. These guidelines need to be followed in order to ensure accuracy and efficiency.

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3 years ago

Let $S$ be the set of complex numbers of the form $a + bi,$ where $a$ and $b$ are integers. We say that $z \in S$ is a unit if t

lakkis [162]

Answer:

Number of units possible in S are 4.

Explanation:

Given S is a set of complex number of the form $a+bi$ where a and b are integers.

$z\in S$ is a unit if $w\in z$ exists such that $zw=1$ .

To find:

Number of units possible = ?

Solution:

Given that:

$zw = 1$

Taking modulus both sides:

$|zw| = |1|$

Using the property that modulus of product of two complex numbers is equal to their individual modulus multiplied.

i.e.

$|z_1z_2|=|z_1|.|z_2|$

So,

$|zw| = |1|\\\Rightarrow |zw| =|z|.|w| =1\\\Rightarrow |z|=\dfrac{1}{|w|}$ ......... (1)

Let $z=a+bi$

Then modulus of z is $|z| = \sqrt{a^2+b^2}$

Given that a and b are integers, so the equation (1) can be true only when $|z| = |w| =1$ (Reciprocal of 1 is 1). Modulus can be equal only when one of the following is satisfied:

(a = 1, b = 0) , (a = -1, b = 0), (a = 0, b = 1) OR (a = 0, b = -1)

So, the possible complex numbers can be:

$1.\ 1 + 0i = 1\\2.\ -1 + 0i = -1\\3.\ 0+ 1i = i\\4.\ 0 -1i = -i$

Hence, number of units possible in S are 4.

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3 years ago

Sibila, Inc. sells its product for $40. The variable costs are $18 per unit. Fixed costs are $16,000. The company is considering

Ahat [919]

Answer:

c. It will increase.

Explanation:

Break even point is the level of activity at which a firm neither makes a profit nor a loss.

Break - even units = Fixed Costs ÷ Contribution per unit

therefore,

Existing break-even point in units :

Break - even units = $16,000 ÷ ($40 - $18) = 727.27 or 728 units

New break-even point in units :

Break - even units = $21,000 ÷ ($40 - $16) = 875 units

Conclusion :

The results show that break-even point in units will increase from 728 units to 875 units as a result of the changes

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