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s2008m [1.1K]
3 years ago
14

How do you make a fire with two sticks

Mathematics
1 answer:
Lorico [155]3 years ago
8 0
You rub them together, and if you rub hard and fast enough it will create enough friction for fire
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Graph f(x) = |x - 6| -4
LekaFEV [45]

Answer:

Step-by-step explanation:

Graph the parent function y = |x|.  This graph has a v shape with vertex at (0, 0) and opens up.

Now translate the entire graph 6 units to the right.  The vertex will now be at (6, 0).

Finally, translate this most recent graph 4 units down.  The vertex will now be at (6, -4).

4 0
3 years ago
08.01) Which of the following statements shows a characteristic of a statistical question? (4 points) Select one: a. The questio
Alexeev081 [22]

Answer:

the distribution can be broken into categories

7 0
3 years ago
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Mr johnson's students want to know his age. He tells them that this year his age is a multiple of 9, and next year it will be a
vladimir1956 [14]

Answer:

He is 27 years old.

Step-by-step explanation:

27 is a multiple of 9 (9 x 3)

28 comes after, and is a multiple of 4 (4 x 7)

Hope this answer helps you!! :)

8 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
What is 75 2/5% in decimal
krok68 [10]

Answer:

.754

Step-by-step explanation:

Percentage is based off of 1 or 100% which is equal to 1. So 50% or half of both 100% and 1 would be translated as .5 and as the percentage becomes more accurate or lengthy you add to the decimal so 53% is .53 and 53.4% is .534

7 0
3 years ago
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