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Anna35 [415]
3 years ago
8

PLEASE HELP ME!!!! I can't seem to get this right!

Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0
Use the law of sines when you're given: (a) 2 angles, 1 side OR (b) 2 sides, non-included angle (aka an angle not created by those two sides)

Use the law of cosines when you're given: (a) 3 sides OR (b) 2 sides, included angle

Since you're given the measurements of two angles (A and C) and one side (a), you can solve the triangle using the law of sines.

Start by drawing the triangle. Remember that the uppercase letters are the angles and the lowercase letters are the length of the sides opposite the angle with the same letter (see picture - letters in blue are given, letters in green are what we're trying to find).

The law of sines says: 
\frac{a}{sin(A)} =  \frac{b}{sin(B)} =  \frac{c}{sin(C)}

1) You are told that angle A = 40°, angle C = 70°, and side a = 20. That means you can plug these values into \frac{a}{sin(A)} = \frac{c}{sin(C)} (which we know is true because of the law of sines) to find the length of side c:
\frac{a}{sin(A)} = \frac{c}{sin(C)}\\ \frac{20}{sin(40\°)} = \frac{c}{sin(70\°)}\\ c = \frac{20sin(70\°)}{sin(40\°)} \\ c \approx 29.238

The length of side c is about 29.238.

2) Also remember that all the angles in a triangle add up to 180°. We know two of the angles, A and C, so subtract A and C from 180 to find the measure of angle B:
\angle B = 180\° - 40\° -  70\° = 70\°

The measure of angle B is 70°.

3) Now you can use the law of sines to find the length of side B. You can use \frac{a}{sin(A)} = \frac{b}{sin(B)} or  \frac{c}{sin(C)} = \frac{b}{sin(B)}. I'll be using the first one:
\frac{a}{sin(A)} = \frac{b}{sin(B)} \\
\frac{20}{sin(40\°)} = \frac{b}{sin(70\°)}\\
b = \frac{20sin(70\°)}{sin(40\°)}\\
b \approx 29.238


The length of side b is also about 29.238.
You can also say b ≈ 29.238 without doing that math because triange ABC is an isosceles triangle since two angles (C and B) are the same, which makes their corresponding sides (c and b) the same! 

-----

Your answer: C) B = 70°, b = 29.2, c = 29.2

Mekhanik [1.2K]3 years ago
5 0
A. is the solution. B. Cannot be solution because there is no one side measurement that is higher than the others. The hypotenuse is always the longest side of the triangle. From this we can rule out C. as well. Finally, we can rule out D., because the angle measures do not add up to 180 degrees, as any real triangle does. Therefore, the answer must be A.
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denpristay [2]

Answer:

0.45

here's your solution

=>. percent = divided by 100

=> so, 45% = 45/100

=> 9/20

= > 0.45

hope it helps

5 0
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Please answer this...​
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2 in the first column and 5 in the second column
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On April 11, 2012, two earthquakes were measured off the northwest coast of Sumatra. The first had a magnitude of 8.6. The secon
Hoochie [10]

Answer:

Option D. 2.51 is correct.

Step-by-step explanation:

Magnitude of first earthquake = 8.6

Let intensity of first earthquake be x

Magnitude = \log(\frac{x}{S}),\text{ where S is seismographic factor}\\\\\implies 8.6=\log(\frac{x}{S}).......(1)

Magnitude of second earthquake = 8.2

Let intensity of second earthquake be y

Magnitude = \log(\frac{y}{S}),\text{ where S is seismographic factor}\\\\\implies 8.2=\log(\frac{y}{S}).......(2)

Now, to find the factor by which intensity of first earthquake is greater than intensity of second : we divide equation (1) by equation (2)

\implies\log(\frac{x}{y})=8.6 - 8.2\\\\\implies \log(\frac{x}{y})=0.4\\\\\implies\frac{x}{y}=10^{0.4}\\\\\implies\frac{x}{y}=2.51

Hence the required factor is 2.51

Therefore, Option D. 2.51 is correct.

4 0
3 years ago
The distance between two cities is 220km. There are approximately 8km in 5 miles. What is the distance in miles?
Free_Kalibri [48]

So i did 220 ÷ 8 and got 27.5 then multiplied by 5 to find how many miles and its 137.5

7 0
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torisob [31]

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8 0
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