Answer: 20.833mph.
Step-by-step explanation:
Using the motion Formula,
speed = distance/time.
This means:
distance = speed * time.
To find the value of "s" in the question, we have to calculate the distance both trains travelled in terms of "s" and sum it to give us 300miles.
For train A,
Speed = S miles per hour
time taken to reach current position= 7hours.
Hence, the distance travelled by train A
Distance A = 7s.
For train B,
Speed= (S + 10)miles per hour.
time taken to reach current position= 5hours (since train B left two hours after the departure of train A)
Distance = speed * time
Distance B = (S + 10) * 5
Distance B = 5s + 50.
Hence, adding both distance to sum up to 300miles, it becomes:
300 = 7s + 5s + 50
300-50 = 12s
250 = 12s
s = 20.833mph.
Answer:
This is the best solution for your question
Answer:
2nd option
Step-by-step explanation:
Given
3x³ - 15x² - 4x + 20
step 1 ( group the first/second and third/fourth terms )
(3x³ - 15x² ) + (- 4x + 20)
step 2 ( factor each group )
3x² (x - 5) - 4(x - 5) ← note factor of - 4 ( not + 4 )
step 3 ( factor out (x - 5) from each term )
(x - 5)(3x² - 4)
Answer:
Step-by-step explanation:
so you will move constant to the right side and change the sign. 72x=223-7
then you will subtract the numbers 72x=223-7 and that will give you 72=216
then you will divide both sides by 72 and that will give you
- x=3 .
