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3 years ago

Algebra- systems of equations (x,y) 3x + 4y = 56 x = 3y + 12

Mathematics

1 answer:

ElenaW [278]3 years ago

7 0

Answer:

Step-by-step explanation:

simplify......dndjddjejdjdjehdeww

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Selma uses a jogging trail that runs through a park near her home. The trail is a loop that is 3/4 of a mile long. On Monday, Se

KIM [24]

(3/4) / (1/6) =
3/4 * 6/1 =
18/4 =
4.5 miles per hr <==

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3 years ago

What does it mean for a scatter plot to have a negative trend? A. Higher x-values tend to go with higher y-values. B. Higher x-v

BARSIC [14]

Answer:

Option D = None of these are related

Step-by-step explanation:

A scatter plot is said to have a negative trend if both x & y values are negative from the origin (0,0)

7 0

3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

mr_godi [17]

Plug the points into the equation.
Ex. y=3x-5
(X,y)
1. (5,10): 10=3(5)-5
15-5=10; point 1 is valid
-1=3(-2)-5
-1=-6-5
-1 does not equal -11
Point 2 is not valid
Same process for letter B

8 0

3 years ago

If 5 is decreased by 3 times a number, the result is negative four

JulsSmile [24]

No. It would be negative 5.

7 0

2 years ago