What are the coordinates of the x and y intercepts of the equation 3x+2y=12
1 answer:
To find the x-intercept you must make y=0
3x+2y=12 - substitute 0 for y
3x+2(0)=12 - multiply 2 and 0
3x+0=12 - add zero
3x=12 - divide by 3
x=4
To find the y-intercept you must make x=0
3x+2y=12 - substitute 0 for x
3(0)+2y=12 - multiply 3 and 0
0+2y=12 - add 0 and 2y
2y=12 - divide by 2
y=6
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A is the answer to the question.
The value of 0 is 20squRed to the dp of 35
I would say C 9 because the only term with a 9 in it is 9f4g
1 = 2 = 3 = 90
4 = 113
5 = 6 = 67
8 = 23
7 = 9 = 157
2 1/3 + 2 1/2 = 4 + 1/3 + 1/2 = 4 + 2/6 + 3/6 = 4 + 5/6 ( both recipe );
5 - ( 4 + 5/6) = 1 - 5/6 = 6/6 - 5/6 = 1/6 cups of flour left;
