The company installs 5000 light bulbs with an average of 500 hours for each bulb. The standard deviation of 100 hours and distribution approximated by a normal curve. The percentage of bulbs that can be expected to last the period of time of less than 690 hours is 97.1%. This will make the answer to be C.
Answer:
1
Step-by-step explanation:
For the top, you can write it as (2-b)^2 = (-1(b-2))^2 = (-1)^2(b-2)^2 = 1(b-2)^2 = (b-2)^2. Putting that back in, we get: ((b-2)^2)/((b-2)^2) = 1 because the top and bottom cancel.
I hope this helps! :)
Answer:
1/3
Step-by-step explanation: