Ow... this geometry is sure hard!!
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Wait a second. Nope.
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TWO SIDES!!
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ITT!!
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CONVERSE ITT!!
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Converse Isosceles Triangle Theorem!
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Look at the picture I attached.
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Two angles equal... THE SIDES ADJACENT TO IT EQUAL!!
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PERFECTO!!
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Hope I helped!!
Source: I am learning Honors Geometry, near end of course.
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:

Substitute for the values of AC, BC, DF and EF:


To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.

Substitute for the values and solve:


We have the value x to be 5.5 units and y to be 6 units.
Answer:
Where is the question or problem that you want answered?
Step-by-step explanation:
I won't be of much help if I do not know what is it that you are asking help for.
Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac
(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8