Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Isolate the variable by dividing each side by factors that dont contain variables
Answer: x=3
Answer:
$1562
Step-by-step explanation:
so she will get less so 1347 copies well be $1562
Answer:
70
Step-by-step explanation:
We have the final part 4x/40 = 7. We can simplify this to x/10 = 7 by dividing the numerator and the denominator by 4. We then multiply both sides by 10 to get x = 70
−
9
Explanation:
(
3
i
)
2
=
9
i
2
i
2
=
−
1
,
therefore,
9
i
2
=
9
⋅
(
−
1
)
=
−
9
