Solve for x: 4(x+6) = 2-6 (x+3)

Given the following scenario, decide if it is a permutation or combination. Then calculate the number of possibilities. (Please

sergey [27]

The right answer for the question that is being asked and shown above is that:

There are...
15 * 14 * 13 * 12 ways in order to know the four finalists.
This is equal to 32,760 ways i n order to know the four finalists.

6 0

3 years ago

You are making cookies for a party. The ratio of Cookie Tray A to Cookie Tray B to Cookie Tray C is 2 : 3 : 4. If you need to ma

Elenna [48]

Given that the ratio of three trays is A : B : C = 2 : 3 : 4

Let us consider the common factor among the number of trays be "x".

If we need to make a total of 171 trays, then the equation of sum of trays would be :-

Type A + Type B + Type C = 171

2x + 3x + 4x = 171

9x = 171

x = $\frac{171}{9}$ = 19

So we have following number of trays :-

Number of type A trays = 2x = 38 trays.

Number of type B trays = 3x = 57 trays.

Number of type C trays = 4x = 76 trays.

Now if each tray contains 20 cookies, then we would have following arrangements :-

Cookies in type A trays = 38×20 = 760 cookies.

Cookies in type B trays = 57×20 = 1140 cookies.

Cookies in type C trays = 76×20 = 1520 cookies.

4 0

3 years ago

What numbers are the arrows pointing to ???

Allushta [10]

Answer:

Step-by-step explanation:

36

6.4

9.3

6 0

4 years ago

Read 2 more answers

The probability of choosing a green marble from a bag is 1/8 and blue marble is 3/8. what is the probability of not choosing one

Ksenya-84 [330]

4/8 or 1/2

hope this helped

5 0

3 years ago

t^2+4t+4 t^2-2t+1 Consider the parametric curve a. Find points on the parametric curve where the tangent lines are vertical. b.

kondaur [170]

Answer:

a) $t = 1$ , b) $t = -2$ , c) Concave upward: $(-\infty, 1)$ . No intervals being concave downward.

Step-by-step explanation:

a) Tangent line is vertical if slope is undefined, whose points are associated with discontinuities of the function. Rational functions have discontinuities associated with the denominator:

$f(t) = \frac{t^{2}+4\cdot t +4}{t^{2}-2\cdot t + 1}$

By factorizing each component, the function is re-arranged as:

$f(t) = \frac{(t+2)^{2}}{(t-1)^{2}}$

There is no avoidable discontinuities. The only point where tangent line is vertical is $t = 1$ .

b) Tangent line is horizontal if slope is equal to zero, whose point is associated to the points that makes function equal to zero. Rational functions have horizontal tangent lines if numerator is equal to zero and denominator is different to zero. Hence, the only point where tangent line is horizontal is $t = -2$ .

c) An interval is concave upward if exist an absolute minimum inside, which can be found by the help of the First and Second Derivative Tests.

$f'(t) = \frac{2\cdot (t+2)\cdot (t-1)^{2}-2\cdot (t-1)\cdot (t+2)^{2}}{(t-1)^{4}}$

$f'(t) = 2\cdot (t+2)\cdot (t-1)\cdot \left[\frac{t-1-t-2}{(t-1)^{4}}\right]$

$f'(t) = -\frac{6\cdot (t+2)\cdot (t-1)}{(t-1)^{4}}$

$f'(t) = -\frac{6\cdot (t+2)}{(t-1)^{3}}$

The only critical point is:

$-6\cdot (t+2) = 0$

$t = -2$ (which coincides with the result of point b)

$f''(t) = -6\cdot \left[\frac{(t-1)^{3}-3\cdot (t-1)^{2}\cdot (t+2)}{(t-1)^{6}}\right]$

$f''(t) = -6\cdot \left[\frac{1}{(t-1)^{3}}-\frac{3\cdot (t+2)}{(t-1)^{4}} \right]$

The value associated with the critical point is:

$f''(-2) = \frac{2}{9}$

Which means that critical point is an absolute minimum, and, consequently, the interval that is concave upward is $(-\infty, 1)$ . There is no absolute maximums and, therefore, there is no interval that is concave downward.

7 0

4 years ago