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3 years ago

Solve for x: 4(x+6) = 2-6 (x+3)

Mathematics

1 answer:

laiz [17]3 years ago

6 0

Answer:

x = - 4

Step-by-step explanation:

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All cell phone plans from Mobile USA require an additional $10/month data fee on top of the base plan price.

Natasha2012 [34]

Answer:

Step-by-step explanation:

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3 years ago

Use the given conditions to write an equation for the line in point-slope form.

Alex17521 [72]

Step-by-step explanation:

Hey there!

The given slope is; 3. And passing through point (-7,8).

Now,

Using one point formula.

$(y - y1) = m(x - x1)$

Put all values to find equation.

$(y - 8) = 3(x + 7)$

Simplify them to get answer.

$(y - 8 )= 3x + 21$

$3x - y + 21 + 8 = 0$

$3x - y + 29 = 0$

Therefore the required equation is 3x-y+29=0.

Hope it helps...

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3 years ago

If an equation is an identity, then how many solutions does it have?

olga2289 [7]

Hello,

If an equation is an identity, then every value of the variable makes the egality true.

Generaly we resolve an equation in R.

In this case Sol=R

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4 years ago

Read 2 more answers

The reciprocal of my number is one fewer than the sum of the reciprocals of the two largest single digit prime numbers. What is

antoniya [11.8K]

The answer would be 2

7 0

3 years ago

Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.

Digiron [165]

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

$x ^ 2-1 = 0\\x ^ 2 = 1$

So the roots are:

$x = 1\\x = -1$

Therefore we can write the expression in the following way:

$x ^ 2-1 = (x-1)(x + 1)$

Now the expression is as follows:

$\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0$

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

$x = 1\\x = -1\\x = 2$

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

$(x-1)\geq0$ when $x\geq-1$

$(x + 1)\geq0$ when $x\geq1$

and

$(x-2) ^ 2$ is always $\geq0$

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

6 0

3 years ago