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Alex73 [517]
3 years ago
11

Let X and Y be the following sets:

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

<u>Given</u>:

Let X and Y be two sets.

The two sets are given by X=\{5,10,15\} and Y=\{3,6,9,12,15\}

We need to determine the value of the set X \cup Y

<u>Value of the set </u>X \cup Y<u>:</u>

The value of the set X \cup Y is the set that contains all the elements that are at least in one of the two sets.

Hence, the union of the set X \cup Y is given by

X \cup Y=\{5,10,15\} \cup \{3,6,9,12,15\}

X \cup Y=\{5,10,15,3,6,9,12\}

Arranging in ascending order, we get;

X \cup Y=\{3,5,6,9,10,12,15\}

Thus, the union of the sets X and Y is X \cup Y=\{3,5,6,9,10,12,15\}

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Solve 2 1/2 divided by 5 1/3 = 8/x
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2\frac { 1 }{ 2 } \quad divided\quad by\quad 5\frac { 1 }{ 3 } \\ \\ 2\frac { 1 }{ 2 } =2+\frac { 1 }{ 2 } =\frac { 5 }{ 2 } \\ \\ 5\frac { 1 }{ 3 } =5+\frac { 1 }{ 3 } =\frac { 15+1 }{ 3 } =\frac { 16 }{ 3 } \\ \\ \\ \frac { \frac { 5 }{ 2 }  }{ \frac { 16 }{ 3 }  }

We're dividing fractions, so we will flip the one in the denominator upside down and we will multiply it with the numerator.

\frac { \frac { 5 }{ 2 }  }{ \frac { 16 }{ 3 }  } \quad =\quad \frac { 5 }{ 2 } \cdot \frac { 3 }{ 16 } =\frac { 5\cdot 3 }{ 2\cdot 16 } =\frac { 15 }{ 32 }

Let's equal this too 8/x

\frac { 15 }{ 32 } =\frac { 8 }{ x }

Cross multiply. 

8\cdot 32=15\cdot x\\ \\ 256=15x

Divide both sides by 15.

\frac { 256 }{ 15 } =\frac { 15x }{ 15 } \\ \\ \frac { 256 }{ 15 } =x

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these numbers in order are 2, 5, 6, 8, 12, 15, 19, 22 and the middle numbers are 8 and 12

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Step-by-step explanation:

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