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mote1985 [20]
2 years ago
5

Please help,thank you

Mathematics
1 answer:
expeople1 [14]2 years ago
5 0

Answer:

No, It is not a function!

Step-by-step explanation:

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Help please it would help my grade alot
Alexxandr [17]

Answer:

It cooled 58.4 degrees

Step-by-step explanation:

T(t) = 68 + 144e ^(-.052t)

We want to find the value when t= 10

T(10) = 68 + 144e ^(-.052*10)

        = 68 +85.611

 T(10)         =153.611

We also need to know

T(0)= 68 + 144e ^(-.052*0)

       =68+144

        =212

We want to know how much it cools

That would be the temperature at  time 0 minus the temperature at  time 10


T(0) - T (10)

212-153.611

58.389

To the nearest tenth

58.4 degrees

3 0
2 years ago
Just need help with 6 please
alexdok [17]

Answer:

Congruent, SSS

Step-by-step explanation:

The dashes on the sides of the triangles represent that the corresponding lengths of the triangles are equal in length. Since it is given that all corresponding lengths of the triangles are equivalent, the triangles are congruent by the SSS (side, side, side) test.

Hope this helps :)

4 0
3 years ago
A man is listening to his radio at the top of a mountain where the altitude is 4500 feet
AURORKA [14]
But what say it again wit what is this
7 0
2 years ago
The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
2 years ago
Find a distance between the two points
Alekssandra [29.7K]

i dont seem to understamd

6 0
3 years ago
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