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4 years ago

Are functional strategies interdependent, or can they be formulated independently of other functions?

Computers and Technology

2 answers:

Diano4ka-milaya [45]4 years ago

5 0

Answer:

Functional strategies are interdependent

Explanation:

Although functional strategies are usually formed separately, they are somewhat interrelated as a result of some factors.

First, we know that despite the fact that functional strategies can be formed in isolation, they still have to be in coordination with other functions. An example is that if an organization formulates a financial strategy, its implementation depends on more than just the finance function, but also on other functions. Also, from definition, we say that functional strategies are plans formulated by companies for human resources, sales, marketing, finance, and other functional areas. It supports line management and also both business strategy and corporate-level strategy, and hence it can be said that they are interdependent.

Vikentia [17]4 years ago

3 0

Answer:

Functional strategies are interdependent based of organizational strategies.

Explanation:

An organization is a group or encompasses a collection of departments, focused on assigned Target and objectives for each departments, to meet or achieve a general goal. Functional strategies are processes chosen by a department to execute a task.

Functional strategies are actually drafted independently in which departments, but the departmental goals are interrelated, making the their functional strategies interdependent to meet the organizational goals.

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3 years ago

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3 years ago

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3 years ago

Define a function CoordTransform() that transforms the function's first two input parameters xVal and yVal into two output param

gogolik [260]

Answer:

Here is the function CoordTransform() that transforms the function's first two input parameters xVal and yVal into two output parameters xValNew and yValNew

void CoordTransform (int xVal ,int yVal ,int& xValNew, int& yValNew) { //function definition

xValNew = (xVal +1) *2; // adds 1 to old value (xVal) , multiplies the result by 2 and assigns that new value to xValNew

yValNew = (yVal +1) *2; } // adds 1 to old value (yVal) , multiplies the result by 2 and assigns that new value to yValNew

Explanation:

Here is the complete program:

#include <iostream> //to use input output functions

using namespace std; // to access objects like cin cout

void CoordTransform (int xVal ,int yVal ,int& xValNew, int& yValNew) { //function that takes four arguments

xValNew = (xVal +1) *2; // computes new value and assigns it to xValNew

yValNew = (yVal +1) *2;} // computes new value and assigns it to yValNew

int main() { // start of main function

//declares 4 int type variables xValNew, yValNew, xValUser, yValUser

int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser; // takes value of xValUser from user

cin >> yValUser; // takes value of yValUser from user

CoordTransform(xValUser, yValUser, xValNew, yValNew); //function call

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl; //prints the old and new values

return 0;}

In this program the function CoordTransform receives a reference to a variables xValNew and yValNew so that it can modify the values of these variables. So xValNew and yValNew variables are declared as reference so they become an alternative name for the variables xValNew and yValNew used in main() method . These variables are declared as reference in the function CoordTransform() by placing ‘&’ symbol in the declaration.

Suppose user enters 3 as value of xValUser and 4 as value of yValUser

Now when the function CoordTransform() is called it works as follows:

xValNew = (xVal +1) *2; this statement becomes:

xValNew = (3 + 1) * 2

xValNew = 4 * 2

xValNew = 8

Now this value is assigned to the xValNew of calling function (main) xValNew variable.

yValNew = (yVal +1) *2;

this statement becomes:

yValNew = (4 + 1) * 2

yValNew = 5 * 2

yValNew = 10

Now this value is assigned to the yValNew of calling function (main) yValNew variable.

So the output of the above program is:

(3, 4) becomes (8, 10)

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3 years ago