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3 years ago

Which logic gate produces an output of 1 only if both it’s inputs are 0?

Computers and Technology

2 answers:

ElenaW [278]3 years ago

5 0

Answer:

the nand gate

dedylja [7]3 years ago

5 0

It’s the nand gate that’s the answer

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At the beginning of Section 5.2, it is stated that multiprogramming and multiprocessing present the same problems, with respect

QveST [7]

Answer:

By definition, <u>multiprocessing</u> refers to the processing of multiple processes at the same time by multiple CPUs.

By definition, <u>multiprogramming</u> keeps programs in main memory at the same time and execute them concurrently utilizing a single CPU doing a context switch.

The first difference is that multiprocessing uses multiple CPUs and multiprogramming to utilize context switch to do concurrency in one CPU. Another difference is that multiprocessing is more expensive but more efficient than multiprogramming due that it allows parallel processing.

6 0

3 years ago

Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type

sattari [20]

Solution :

#include $$$$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal $\text{To}$ Binary(char* hexdec)

{

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$ (sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0

3 years ago

Question 4

Tcecarenko [31]

Answer: squared ← number * number

Explanation:

4 0

3 years ago

What is a list of data organized for easy access?

ozzi

Answer:

An Array

Explanation:

Array and Object is a good use for storing data and accessing it

6 0

2 years ago

g Create a program that reads a list of states from an input file, puts them in order, and displays the sorted list to the user.

mixas84 [53]

Answer:

Check the explanation

Explanation:

# Step 1

the first thing to execute will be......

f = open("states.txt")

# Step 2

the second step is......

states = []

for line in f:

states.append(line.strip())

# Step 3:

the third step is to......

for state in sorted(states):

print(state)

f.close()

3 0

3 years ago