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vekshin1
4 years ago
13

Solve for x.

Mathematics
2 answers:
kkurt [141]4 years ago
6 0
The answer is x=6.1 i believe 
Montano1993 [528]4 years ago
5 0
The answer is x=6.1 hope this helped
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If the integers a and n are greater than 1 and the product of the first 8 positive integers is a multiple of a^n, what is the va
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Answer:

a=2

Step-by-step explanation:

Well, first let us find product of the first 8 positive integers, which is 1*2*3*4*5*6*7*8=40320. It can also be written as 40320=2^{7}*3²*5*7. From the formula above, it can be extracted that if a=2, n can be any number from 3 to 7 (considering that a and n are not equal and greater than 1).

In (1) a^n=64 and in (2) n=6 so it can be written as 2^6=64 so a=2 and n=6. So the value of a is 2. a=2

3 0
3 years ago
??? I need help on this question
Solnce55 [7]
Let x be 1st and y the 2nd number in the solution:

x=y+21

.2x=y

x=.2x+21

.8x=21

x=26.25 larger number

y=5.25 smaller number


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