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tamaranim1 [39]
3 years ago
10

In Christopher Marlowe's The Tragical History of Doctor Faustus, why did Faustus begin to believe that human salvation was impos

sible? Faustus first began to believe that human salvation was impossible because In addition, he had
Mathematics
1 answer:
Reika [66]3 years ago
6 0
In Christopher Marlowe's The Tragical History of Doctor Faustus, Faustus began to believe that human salvation was impossible because <span>he read the scripture and saw that all human beings sin and are doomed. He thought that this meant that no matter how you lived your life, and how much you tried to be a good person, in the end you would still sin and thus God won't forgive you. This is why he consciously gave in to sin. 

In addition, he had </span><span>been misled by Mephastophills, who caused him to misread the scriptures. Mephastophills is the Devil, and obviously the Devil won't tell the truth because he wants to collect more souls to torture in his realm. Faustus fell for his tricks and was mislead to misinterpret the scriptures, which lead to him losing his soul ultimately. </span>
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Formula for volume of cone:

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Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

V=9\int\limits^2_0 {4y^{3}/3} \, dy

After performing the elementary y integral we obtain the desired volume as below,

V= 48 units^{3}

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