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Aleks [24]
3 years ago
5

A triangle has side lengths of (2.4k-7.4) centimeters, (6.3k-2.2) centimeters and (6.8m+2.4) centimeters. which expression repre

sents the perimeter, in centimeters, of the triangle?
a. 9.2m-0.9k
b.-9.6+9.2m+8.7k
c. 6.8m-7.2+8.7k
d. -5k+4.1+9.2m
Mathematics
1 answer:
MrRa [10]3 years ago
6 0

c. 6.8m-7.2+8.7k

(2.4k-7.4)+(6.3k-2.2)+(6.8m+2.4) combine like terms

2.4k+6.3k+6.8m-7.4-2.2+2.4\\9.7k+6.8m-9.6+2.4\\9.7k+6.8m-7.2

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Need help again. Please explain your answer.
Elis [28]

4y + 3 ≤ y + 6

4y + 3 - 3 ≤ y + 6 - 3

4y ≤ y + 3

4y - y ≤ y - y + 3

3y ≤ 3

3y/3 ≤ 3/3

y ≤ 1

So any value of y less than or equal to 1 (so 1 is included in the solution set) satisfies the inequality. C is the correct answer.

5 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
1<br> Which sequence of transformations takes AA to its image, AB ?
lianna [129]

A rigid transformation preserves the dimensions of the image

The option that gives the sequence of transformation that takes ΔB to ΔB is  the option B.

<u>(B) Reflection across y-axis and a translation 2 units down </u>

Reason:

Question: The sequence of transformation that takes ΔA to image ΔB

<em>From a similar question, we have, ;</em>

<em>The vertices of triangle ΔA are; (-8, 9), (-9, 4), (-3, 4)</em>

<em>The vertices of triangle ΔB are; (8, 7), (3, 2), (9, 2)</em>

<em>The options are; </em>

<em>(A) Reflection over the x-axis and 2 units translation down</em>

<em>(B) Reflection over the y-axis and 2 units translation down</em>

<em>(C) 90° rotation after a translation of 2 units down</em>

<em>(D) 90° rotation after a translation of 12units right</em>

Solution;

The length of the base of ΔA = -3 - (-9) = 6

The length of the base of ΔB = 9 - 3 = 6

Therefore, the length s of triangle A and triangle B are equal

The orientation of the base of ΔA and ΔB are both horizontal

The location of the the side that traverses four cells are both furthest from the y-axis, or the vertical

Therefore, ΔB is a reflection of ΔA across the y-axis

We also have;

The base of ΔB is 2 units lower than the base ΔA

Therefore, the correct option is option B, reflection across y-axis and a translation 2 units down

Learn more here;

brainly.com/question/23461633

7 0
3 years ago
Multiply Conjugates Using the Product of Conjugates Pattern
weeeeeb [17]

Answer:

The product is the difference of squares is $$\left(xy-9\right)\left(xy+9\right)={{x}^2}{{y}^2}-81$$

Step-by-step explanation:

Explanation

  • The given expression is (x y-9)(x y+9).
  • We have to multiply the given expression.
  • Square the first term xy. Square the last term 9 .

$$\begin{aligned}&(x y-9)(x y+9)=(x y)^{2}-(9)^{2} \\&(x y-9)(x y+9)=x^{2} y^{2}-81\end{aligned}$$

5 0
2 years ago
A slice is made perpendicular to the base of a right rectangular prism as shown.
Eduardwww [97]

Answer:

The correct option is 1. The area of cross section area is 48 mm².

Step-by-step explanation:

From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.

The area of a rectangle is the product of its dimensions.

A=l\times w

Where, l is length of the rectangle and w is width of the rectangle.

The area of cross section is

A=4\times 12

A=48

Therefore the area of cross section area is 48 mm². Option 1 is correct.

8 0
3 years ago
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