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vfiekz [6]
3 years ago
5

Solve. 3a + 3b + c = - 33 a-3b + 2c = -1 8a-2b + 3c What is the solution?

Mathematics
2 answers:
Alik [6]3 years ago
8 0
I ave the answer i just can’t put it
bagirrra123 [75]3 years ago
5 0
I think the solutions is....... actually i don’t know only did this for points good luck !
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Which expression is equivalent to −4(2x − 8)−2x ?
Vesnalui [34]
C. -10x+32

Explanation: Solve the problem
( -4(2x-8)-2x )
5 0
2 years ago
In the given figure p=120° and y : z=2 : 3 Find x, y and z​
Sindrei [870]

Answer:

x = 60°

y = 72°

z = 48°

Step-by-step explanation:

x = 180 - p = 180 - 120 = 60

Since y;z = 3:2 ,   2y = 3z  or z = 2y/3

Now, x + y + z = 180

60 + y + 2y/3 = 180     Multiply thru by 3 to remove the fraction

180 + 3y + 2y = 540

180 + 5y = 540

5y = 360

y = 72

z = 2(72)/3 = 48

Check:  60 + 72 + 48 = 180

5 0
3 years ago
The measures of the angles of a triangle are shown in the figure below. Solve for x.
MissTica

Answer: X= 25 degrees

Step-by-step explanation:

A triangle is 180 degrees.

115+40=165

180-165=25 degrees

6 0
3 years ago
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
4 years ago
The price that a company charged for a basketball hoop is given by the equation 50-5x^2 where x is the number of hoops that are
Debora [2.8K]
Given:
Profit : 15,000,000
Cost: 30 per basketball hoop
production: 1 million hoops
price: 50 - 5x²

Profit = Sales - Cost
15,000,000 = sales - 30(1,000,000)
15,000,000 + 30,000,000 = sales
45,000,000 = sales

45,000,000 / 1,000,000 = 45 sales price.




3 0
3 years ago
Read 2 more answers
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