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3 years ago

The side length of a square is (8-√10) inches long. What's the area of the square.

Mathematics

1 answer:

Sergio039 [100]3 years ago

7 0

here .

length of square is (8-√10) inches

to find area of square

we know

are

area of square = (L) square

=(8-√10)square

=64+16√10+10 ( using the formula (a-b) square )

(a square -2ab+b square)

=74-16√10 (adding two numbers)

ANsWEr

therefore the answer will be 74-16√10

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For the period 1997-2003, the number of eggs y (in billions) produced in the United States can be modeled by the function y=-0.2

Viktor [21]

Answer:

Part a) The approximate years were 1998 and 2008

Part b) The graph in the attached figure

Step-by-step explanation:

Part a) we have

$y=-0.27x^{2}+3.3x+77$

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Solve the quadratic equation

$80=-0.27x^{2}+3.3x+77$

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we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$0.27x^{2}-3.3x+3=0$

$a=0.27\\b=-3.3\\c=3$

substitute in the formula

$x=\frac{3.3(+/-)\sqrt{-3.3^{2}-4(0.27)(3)}} {2(0.27)}$

$x=\frac{3.3(+/-)\sqrt{7.65}} {0.54}$

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$x=\frac{3.3(-)\sqrt{7.65}} {0.54}=0.99\ years$

therefore

The approximate years are

1997+11=2008

1997+1=1998

Part b)

Using a graphing tool

we have

$y=-0.27x^{2}+3.3x+77$

$y=80$

The solution of the system of equations is the intersection point both graphs

The intersection point are (0.99,80) and (11.23,80)

see the attached figure

therefore

The solution part a) is correct

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