A recreational court is three times as long as it is wide. If the perimeter is 224 ft, find the dimensions of the court?
1 answer:
The dimensions of court are:
Length = 84 feet and Width = 28 feet
Step-by-step explanation:
Given
Perimeter of court = 224 ft
Let l be the length and w be the width
then
l = 3w
The formula for perimeter of rectangle is:
Putting the value
Dividing both sides by 8
Length:
Hence,
The dimensions of court are:
Length = 84 feet and Width = 28 feet
Keywords: Perimeter, rectangle
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Answer:
Step-by-step explanation:
Draw a line from point ( 0.6, 0.8 ) to the X - axis, forming a right triangle with hypotenuse = r = 1 , adjacent = 0.6, opposite = 0.8
The maximum height of the rocket is 43.89 feet
<h3>How to write the function</h3>The general function is given as:
h(t) = -16t^2 + vt + h
The initial velocity is
v = 53
So, we have:
h(t) = -16t^2 + 53t + h
The initial height is
h = 0
So, we have:
h(t) = -16t^2 + 53t
Hence, the function of the height is h(t) = -16t^2 + 53t
<h3>The maximum height of the rocket</h3>
In (a), we have:
h(t) = -16t^2 + 53t
Differentiate the function
h'(t) = -32t + 53
Set to 0
-32t + 53 = 0
This gives
-32t = -53
Divide by -32
t = 1.65625
Substitute t = 1.65625 in h(t) = -16t^2 + 53t
h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625
Evaluate
h(1.65625) = 43.890625
Approximate
h(1.65625) = 43.89
Hence, the maximum height of the rocket is 43.89 feet
<h3>Time to hit the ground</h3>In (a), we have
h(t) = -16t^2 + 53t
Set to 0
-16t^2 + 53t = 0
Divide through by -t
16t - 53 = 0
Add 53 to both sides
16t = 53
Divide by 16
t = 3.3125
Hence, the time to hit the ground is 3.3125 seconds
<h3>The graph of the function h(t)</h3>See attachment for the graph of the function h(t)
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