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Lerok [7]
3 years ago
7

I need help with math 2 on gradpoint I’ll literally pay anyone because I need the class to graduate.

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
Hey there, i might be interested in this deal. how much will i be getting paid?
You might be interested in
What is the correct integer for the following: a deposit of $1000?
Sladkaya [172]

Answer: One hundred thousand

 

Step-by-step explanation:

✌️✌️✌️

6 0
3 years ago
I need help with this proof!
mr Goodwill [35]

Answer:

∠B ≅ ∠F ⇒ proved down

Step-by-step explanation:

<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>

Let us use this fact to solve the question

→ In Δs BCD and FED

∵ ∠C and ∠E are right angles

∴ Δs BCD and FED are right triangles ⇒ (1)

∵ D is the mid-point of CE

→ That means point D divides CE into 2 equal parts CD and ED

∴ CD = ED ⇒ (2) legs

∵ BD and DF are the opposite sides to the right angles

∴ BD and DF are the hypotenuses of the triangles

∵ BD ≅ FD ⇒ (3) hypotenuses

→ From (1), (2), (3), and the fact above

∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency

→ As a result of congruency

∴ BC ≅ FE

∴ ∠BDC ≅ ∠FDE

∴ ∠B ≅ ∠F ⇒ proved

3 0
3 years ago
2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

      a -5  = 14

             a = 14 + 5

             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

8 0
2 years ago
Read 2 more answers
Victor got 24 out of 30 correct on his math test. What percent did Victor get correct?
Snowcat [4.5K]

Answer:

\frac{24}{30} x 100 = 80%

Step-by-step explanation:

8 0
3 years ago
HEL----PPPPpppppppppppppppppppppppppppppp
omeli [17]

Answer:

Step-by-step explanation:

First order from smallest to largest.

70.8, 71.9, 72.1, 82.4, 85.3, 98.1.

Median is the middle number/s.

72.1+82.4/2 so The median is 77.25

Range is the largest number minus the smallest number.

85.3-70.8=14.5

Mode is the most repeated number.

Since there are no repeated numbers there is no mode.

Second question:

Again rearrage: 6, 9, 11, 14, 17

In order to make the median 10 you would have to add another 9 becasue

11+9/2 = 10

Third: remove 6 to make 12 the middle number

Fourth: add all numbers 90+x/6=20 so x has to be 30

8 0
3 years ago
Read 2 more answers
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