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Lisa [10]
3 years ago
13

Consider a three sequentially stepped process named as Process A, Process B and Process C. Input comes into Process A. Output fo

rm A goes into Process B. Output from B goes into Process C. Output of C is the final output. Suppose that it takes 2 minutes per unit in Process A, 3 minutes per unit in Process B and 1 minute per unit in Process C. What will be maximum steady state output from this system?
Computers and Technology
1 answer:
Novay_Z [31]3 years ago
4 0

Answer: The process B is at the maximum steady state. A process is said to be at steady state if the variables that define the behavior of the system are unchanging

Explanation: From the Above

Process A takes 2 minutes per unit and hence can process (60/2) = 30 units per hour. Process B can process only (60/3) = 20 units per hour. Process C can handle (60/1) = 60 units per hour. the steady state output from this system is the smallest of the three, that is process B 20 units per hour

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Write a program that accepts a positive integer N as command-line argument, and outputs True if N is the square of some integer,
Ann [662]

Answer:

In Python:

N = int(input("Positive integer: "))

if N > 0:

   flag = False

   for i in range(1,N+1):

       if i * i == N:

           flag = True

           break

   print(str(flag))

else:

   print("Positive integer only")

   

Explanation:

N = int(input("Positive integer: "))

If the number is positive

if N > 0:

This initializes a boolean variable to false

   flag = False

This iterates from 1 to the input integer

   for i in range(1,N+1):

This checks if th number is a square of some integer

       if i * i == N:

If yes, flag is set to true

           flag = True

The loop is exited

           break

This prints either true or false, depending on the result of the loop

   print(str(flag))

If otherwise, that the number is not positive

<em>else:</em>

<em>    print("Positive integer only")</em>

3 0
3 years ago
What is the full form of com​
nignag [31]

The answer is:

Commercial

3 0
3 years ago
A combination lock has the following basic properties:
fomenos

Answer:

public class CombinationLock {

   

    private int combinationNumber1 = 0;

    private int combinationNumber2 = 0;

    private int combinationNumber3 = 0;

   

   CombinationLock(int combinationNumber1, int combinationNumber2, int combinationNumber3){

       this.combinationNumber1 = combinationNumber1;

       this.combinationNumber2 = combinationNumber2;

       this.combinationNumber3 = combinationNumber3;

   }

   

   public boolean open(int number1, int number2, int number3){

       if(number1 == combinationNumber1 && number2 == combinationNumber2 && number3 == combinationNumber3)

           return true;

       else

           return false;

   }

   

   public boolean changeCombo(int number1, int number2, int number3, int newNumber1, int newNumber2, int newNumber3){

       

       if (open(number1, number2, number3)){

           combinationNumber1 = newNumber1;

           combinationNumber2 = newNumber2;

           combinationNumber3 = newNumber3;

           return true;

       }else

           return false;

   }

}

Explanation:

- <em>Three variables</em> are created to hold the combination.

- A <em>constructor</em> is created to set the combination.

- A boolean method called <em>open</em> is created to check if the given numbers are correct, and <u>returns true</u> (<u>otherwise returns false</u>).

- A boolean method method called <em>changeCombo</em> is created to check if given numbers are correct. If they are correct, it assigns new values for the combination and <u>returns true</u> (<u>otherwise returns false</u>).

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Answer:

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