We are given the following variables:
μ = the sample mean = 152 pounds
σ = the standard deviation = 26 pounds
x = the sample value we want to test = 180 pounds
n = the sample size = unknown
MOE = margin of error = 4% = 0.04
Confidence level = 96%
The first thing we can do is to find for the value of z
using the formula:
z = (x – μ) / σ
z = (180 – 152) / 26
z = 1.0769 = 1.08
Since we are looking for the people who weigh more than
180 pounds, therefore this is a right tailed z test. The p value is:
p = 0.1401
Then we can use the formula below to solve for n:
n = z^2 * p * (1 – p) / (MOE)^2
n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2
n = 87.82 = 88
Therefore around 88 people must be surveyed.
Answer:
272
Step-by-step explanation:
calculator
Answer:
y=-2x-5
Step-by-step explanation:
slope (m)= -2, point (-4,3) put in y=mx+B
3 (y)= -2 [m](-4) + B
3=-2 (-4)+B. - multiple -2 and -4
3= 8 +B. - two negatives. multipled gives you a positive
3=8+B. - subtract 8
-8 -8
-5=b
y= -2x-5
Answer:
The correct answer is: A = 1/2 bh V = integral A(x) from [-r, r].
Step-by-step explanation:
x^2 +y^2 = r^2 A = 1/2 bh b = 2y = 2sqrt[r^2 - x^2] so that gives A = 1/2 [ 2sqrt(r^2 - x^2)]h which gives A = sqrt[r^2 - x^2]h
Answer:
Tonnes
Step-by-step explanation:
