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Nitella [24]
3 years ago
6

10. Write an equation to find the value of x.

Mathematics
2 answers:
vitfil [10]3 years ago
6 0

Answer:

x = (180 - 68) / 2

Step-by-step explanation:

x = 56°

Alex787 [66]3 years ago
4 0

Answer:

56°

Step-by-step explanation:

(180° - 68°) ÷ 2 = 112° ÷ 2

= 56°

your welcome :)

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Blababa [14]

Answer:

396m=396m.

your answer is 396m

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6 0
3 years ago
Write a function rule that gives the total cost c(p) of p pounds of sugar if each pound costs $0.59.
Dafna11 [192]

Answer:

D

hope this helps

Step-by-step explanation:


8 0
3 years ago
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Tyler had 2 7/16 yard of fabric. He used 3/4 yard to make a vest. About how much fabric did he have left.
weqwewe [10]
The answer is 1 11/16
4 0
3 years ago
Read 2 more answers
3
Genrish500 [490]

Answer:

See Explanation

Step-by-step explanation:

<em>The question has missing details; However, the following explanation will guide.</em>

<em></em>

Represent the boots print with y and the Liz's feet with x

<em>To calculate how much the boot is longer than her feet, we simply get the difference between the length of the boot's print and her feet;</em>

i.e.

Difference = y - x

<em>Note that her boot print (y) will always be greater than her feet (x)</em>

<em></em>

Take for instance;

y = 3\ ft

x = 2\ ft

The difference will be

Difference = 3ft - 2ft

Difference = 1ft

6 0
3 years ago
The lifetimes of a certain type of light bulbs follow a normal distribution. If approximately 2.5% of the bulbs have lives excee
spin [16.1K]

Answer:

Mean = 339 hours

Standard deviation = 54 hours

Step-by-step explanation:

We are given that approximately 2.5% of the bulbs have lives exceeding 445 hours

So,P(x>445) = 0.025

P(x<445) =1- 0.025 =0.975

 z value for 0.975 is 1.96

Formula : z=\frac{x-\mu}{\sigma}

So, 1.96=\frac{445-\mu}{\sigma}

1.96 \sigma =445-\mu--A

Now we are given that  approximately 16% have lives exceeding 393 hours,

So,P(x>393) = 0.16

P(x<393) =1- 0.16 =0.84

 z value for 0.84 is 1

Formula : z=\frac{x-\mu}{\sigma}

So, 1=\frac{393-\mu}{\sigma}

1 \sigma =393-\mu ---B

Solve A and B

Substitute the value of \sigmafrom B in A

1.96 (393 -\mu) =445-\mu

770.28 -1.96\mu=445-\mu

770.28 -445=1.96\mu-\mu

325.28=0.96\mu

\frac{325.28}{0.96}=\mu

338.83=\mu

Substitute the value in B

\sigma =393-338.83

\sigma =54.17

So, mean = 339 hours

Standard deviation = 54 hours

5 0
4 years ago
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