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4 years ago

What number is 10 times more than 8000

2 answers:

8 0

10*8000= 80,000

An easy way to multiply by 10 is to shift the decimal place over by 1 place value and add a 0 right before it.

Ganezh [65]4 years ago

7 0

80,000 (8,000 x 10= 80,000)

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The headline reporting the results of a poll stated, "Majority of Adults at Personal Best in the Morning." The results indicat

Natasha_Volkova [10]

Answer:

Step-by-step explanation:

Majority is over 50%

6 0

4 years ago

Describe how to determine if two polygons have the same size and shape.

QveST [7]

You can identify similar polygon by comparing their corresponding angles and sides. ( if they are the same the ratio of the lengths is the scale factor. Also check if their sides are proportional.)

4 0

4 years ago

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The age of the children in kindergarten on the first day of school is uniformly distributed between 4.8 and 5.8 years old. A fir

Kazeer [188]

Answer:

(1) (c) 5.30 years.

(2) (b) 0.289.

(3) (b) 0.80.

(4) (d) 0.50.

(5) (a) 5.25 years.

Step-by-step explanation:

Let X = age of the children in kindergarten on the first day of school.

The random variable X follows a continuous Uniform distribution with parameters a = 4.8 years and b = 5.8 years.

The probability density function function of X is:

$f_{X}(x)=\left \{ {{\frac{1}{b-a}} ;\ a$

(1)

The expected value of a Uniform random variable is:

$E(X)=\frac{1}{2}(a+b)$

Compute the mean of X as follows:

$E(X)=\frac{1}{2}(a+b)=\frac{1}{2}\times (4.8+5.8)=5.3$

Thus, the mean of the distribution is (c) 5.30 years.

(2)

The standard deviation of a Uniform random variable is:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}=\sqrt{\frac{1}{12}\times (5.8-4.8)^{2}}=0.289$

Thus, the standard deviation of the distribution is (b) 0.289.

(3)

Compute the probability that a randomly selected child is older than 5 years old as follows:

$P(X>5)=\int\limits^{5.8}_{5} {\frac{1}{5.8-4.8}}\, dx\\$

$=\int\limits^{5.8}_{5} {1}\, dx\\=[x]^{5.8}_{5}\\=(5.8-5)\\=0.8$

Thus, the probability that a randomly selected child is older than 5 years old is (b) 0.80.

(4)

Compute the probability that a randomly selected child is between 5.2 years and 5.7 years old as follows:

$P(5.2$

$=\int\limits^{5.7}_{5.2} {1}\, dx\\=[x]^{5.7}_{5.2}\\=(5.7-5.2)\\=0.5$

Thus, the probability that a randomly selected child is between 5.2 years and 5.7 years old is (d) 0.50.

(5)

It is provided that a randomly selected child is at the 45th percentile.

This implies that:

P (X < x) = 0.45

Compute the value of x as follows:

$P (X < x) = 0.45$

$\int\limits^{x}_{4.8} {\frac{1}{5.8-4.8}}\, dx=0.45$

$\int\limits^{x}_{4.8} {1}\, dx=0.45$

$[x]^{x}_{4.8}=0.45$

$x-4.8=0.45\\$

$x=0.45+4.8\\x=5.25$

Thus, the age of the child at the 45th percentile is (a) 5.25 years.

6 0

3 years ago

A stage designer is making a rectangular drape that is 7 yards in length and 16 yards in width. The fabric for the drape cost $2

USPshnik [31]

Yard to square yard
example: 1yard*1 = 1square yard so 6*6=36 square yards. 7*7=42
36*2.90=104.40
42*2.90=121.8
104.40+121.8=$226.20

6 0

3 years ago

Find the sum of 7/8 and 5/8

Talja [164]

Sum = adding correct.
That means we need to add 7+5 =12
and add the /8 to it

12/8

But thats improper so we need to simplify.

1 4/8

But theres still some simplifying.

4/8=1/2

That means your answer is 1 1/2
Hope this helped :)

3 0

4 years ago

Read 2 more answers