Question

What is the length (magnitude) of vector (6,-3)? Sqrt 53 Sqrt 2 3 3 sqrt 5

Answer 1

Hope this would help you

Answer 2

Answer:

(D)

Step-by-step explanation:

The given vector is  $(6,-3)$, the magnitude of the given vector is gievn as:

$m=\sqrt{(x)^2+(y)^2}$

Putting $x=6$ and $y=-3$, we get

$m=\sqrt{(6)^2+(-3)^2}$

$m=\sqrt{36+9}$

$m=\sqrt{45}$

$m=3\sqrt5$

Thus, the length of the given vector is $3\sqrt5$ units.

Therefore, option D is correct.