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3 years ago

What is the length (magnitude) of vector (6,-3)? Sqrt 53 Sqrt 2 3 3 sqrt 5

Mathematics

2 answers:

vekshin13 years ago

7 0

Hope this would help you

zysi [14]3 years ago

7 0

Answer:

(D)

Step-by-step explanation:

The given vector is $(6,-3)$ , the magnitude of the given vector is gievn as:

$m=\sqrt{(x)^2+(y)^2}$

Putting $x=6$ and $y=-3$ , we get

$m=\sqrt{(6)^2+(-3)^2}$

$m=\sqrt{36+9}$

$m=\sqrt{45}$

$m=3\sqrt5$

Thus, the length of the given vector is $3\sqrt5$ units.

Therefore, option D is correct.

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What is the lowest common multiple of 116 and 196

Ket [755]

Lowest common multiple: 5684
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3 years ago

Two cones are similar. The volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³. The height of the sm

aev [14]

ANSWER

The height of the larger cone is 3cm

EXPLANATION

Since the two cones are similar we can use the scale factor to determine the height of the larger cone.

It was given that, the volume of the larger cone is 27 cm³ and the volume of the smaller cone is 8 cm³.

The scale factor for the volume is

${k}^{3} = \frac{27}{8}$

The scale factor for the length is

$k = \sqrt[3]{ \frac{27}{8} }$

$k = \frac{3}{2}$

To find the height of the larger cone, we multiply by

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7 0

3 years ago

Read 2 more answers

9.5 kiloliters =____deciliters<br> Can someone help?

s2008m [1.1K]

Mulitply the volume value by 10000.

9.5 * 10000 = 95000

Therefore, 9.5 kiloleters = 95000 deciliters.

Please give me brainliest because I gave a step by step explanation of how to solve this problem and the person above me did not.

3 0

2 years ago

Al principio Eduardo y Adrián tenían el mismo número de dulces. Eduardo le dio a Adrián la mitad de los dulces que tenía. Despué

Dennis_Churaev [7]

Answer:

Al final, Eduardo tenía 20 dulces.

Step-by-step explanation:

Dado que al principio Eduardo y Adrián tenían el mismo número de dulces, y Eduardo le dio a Adrián la mitad de los dulces que tenía, y después, Adrián le dio a Eduardo la mitad de los dulces que tenía él en ese momento, así que a Adrián le quedaron 12 dulces, para determinar cuántos dulces tenía Eduardo al final se debe realizar el siguiente cálculo:

Eduardo 1X = Adrián 1X

Eduardo 0.5X = Adrián 1.5X

Eduardo 1.25X = Adrián 0.75X

0.75 X = 12

X = 12 / 0.75

X = 16

1.25 X = 16 x 1.25 = 20

Así, al final, Eduardo tenía 20 dulces.

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3 years ago

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Mumz [18]

Answer:

6? i hope this helps some! :)

Step-by-step explanation:

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3 years ago