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Otrada [13]
3 years ago
14

A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey res

ults for the first-, second-, and third-period classes are as follows:
First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3, 0

Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2

Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3
Mathematics
1 answer:
Yakvenalex [24]3 years ago
8 0
The question would be:

Which is the best measure of center for first period and why?

Mean, because there are no outliers that affect the center

Median, because there is 1 outlier that affects the center

Interquartile range, because there is 1 outlier that affects the center
<span>
I think the answer would be the fourth choice "</span><span>Standard deviation, because there are no outliers that affect the center"
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
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An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, t
irina1246 [14]

Answer:

63.7 inches

Step-by-step explanation:

half the base is 9 inches, so the equal legs are each

L = √(9² +21²) = 22.8473...

Perimeter  = 2(22.8473) + 18 = 63.6946... ≈ 63.7 inches.

3 0
3 years ago
What the heck does this mean? -(-) =
Bond [772]

Answer:

+

Step-by-step explanation:

++ = +

+- = -

-+ = -

-- = +

Example:

-1 x -1 = 1

1 x -1 = -1

3 0
3 years ago
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HELPPPPPPP ME PLEASEE
Svetlanka [38]

Answer:

Step-by-step explanation:

Since they are consecutive angles

You would subtract 180 from 135 to get 45 Measure 2 is 45

5 0
3 years ago
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If a ∝ b and a = 18 when b = 3, then find a when b = 5.
Elden [556K]

"a ∝ b" means "a is proportional to b", which in turn means there is some constant k such that

a = kb

We're given that a = 18 and b = 3, so that

18 = 3k   ⇒   k = 6

Then when b = 5, we would have

a = 6 × 5 = 30

4 0
2 years ago
Plz..... Solve this questions for me...
faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

3 0
3 years ago
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