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JulsSmile [24]
3 years ago
13

Please help me with this :)

Mathematics
1 answer:
djyliett [7]3 years ago
7 0
2.5 and 5 should be the answer
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Find the 6th term in the sequence
Dimas [21]

Answer:

C.64

Step-by-step explanation:

The first step is to figure out what the sequence is, the first step is 2, 4 the only ways for 2 to get to 4 would be +2 or *2 so we will look at the next step, 4 to 8. The only ways for 4 to get to 8 is +4 or *2, since these both have *2 in common we will check that with all of the terms

2, 4, 8, 16, 32

2 (*2) = 4 (*2) = 8 (*2) = 16 (*2) 32

Since the equation is working we are going to multiply 32 by 2 to get the 6th term

32 (*2) = 64

6 0
3 years ago
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Which is the best example of a number written in scientific notation?
lions [1.4K]

Answer:

It would be changing by which a person thinks.

But, I will pick 569.124.

It would be 5.69124e2. (or 5.6912 x 10^3)

3 0
3 years ago
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Graph -7x+5y=35. khan acadmy forms of linear equations question. pls show work (10 points)
a_sh-v [17]

Answer:

Below

Step-by-step explanation:

● -7x + 5y = 35

Add 7x to both sides

● -7x +7x + 5y = 35+7x

● 5y = 7x + 35

Divide both sides by 5

● 5y/5 = (7x+35)/5

● y = 1.4x + 7

The graph of the function:

8 0
3 years ago
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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
Mathematics question help
Nat2105 [25]

Distance Formula: \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}

Point 1: (9,0)

Point 2: (5,-8)

D = sqrt[ (5 - 9)^2 + (-8 - 0)^2 ]

D = sqrt[ (-4)^2 + (-8)^2 ]

D = sqrt[ 16 + 64]

D = sqrt(80)

Hope this helps!

4 0
3 years ago
Read 2 more answers
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