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Andreyy89
3 years ago
9

How do I do #8? Pleas explain thank you

Mathematics
2 answers:
makkiz [27]3 years ago
6 0
Basically what u want to do is take the 36 - 12 and hopefully u should get ur answer which would be 24 inches

kirill [66]3 years ago
5 0
12 inches to 36 inches....if it is increasing (going from a smaller number to a larger number), then it is a percent increase

increase = (new number - original number) / original number...* 100
               = (36 - 12) / 12.....* 100
               = 24/12 * 100
               = 2 * 100
               = 200% increase <==

now as far as a decrease (when it goes from a larger number to a smaller number) the formula is : 
decrease = (original number - new number) / original number..* 100
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Bess [88]
You just divide 3/8= 0.375
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3 years ago
Helppp please if anyone know
zmey [24]
81 - 35+30 (55) = 26 therefore 26cm is ur final answer
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How do you find the area of this (it is not 12 or 18) The First answer gets brainliest
bija089 [108]

Answer:

<em><u>ok the area of a trapezoid is 48 </u></em>

a+b divided by two multiplied by height  

Step-by-step explanation:

each square equals 2 so you count by twos instead of ones..

the height is 8   the base is 8 and the top is 4 so

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6 0
3 years ago
Why is 2 × 3/4 less than 2​
Stella [2.4K]

Answer:

becuase 2*3 is 6, and 2*4 is 8, and when you simplfy it is 1 and 1/2, which in decimal form is 1.5, making it less than 2

5 0
3 years ago
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Help me pls!!!!!!!!!
Dominik [7]

Answer:

x^2+18=-9x : x = -3, x = -6

Step-by-step explanation:

x^2+18=-9x

Add 9x to both sides:

x^2+18+9x=-9x+9x

Simplify:

x^2+9x+18=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}

x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3

x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6

The solution to the quadratic equation are:

x=-3,\:x=-6

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0
3 years ago
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