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iragen [17]
4 years ago
14

Which ordered pair makes both inequalities true?

Mathematics
2 answers:
hammer [34]4 years ago
8 0
None of those pairs can make this inequality true...
Arada [10]4 years ago
8 0

Answer:

All options are wrong.

Step-by-step explanation:

We have y > –3x + 3 and y > 2x – 2

Option A - (1,0)

          y > –3 x 1 + 3 = 0

         We have y = 0, which is not greater than 0.

         Option A is not correct.        

Option B - (–1,1)

          y > –3 x -1 + 3 = 6

         We have y = 1, which is not greater than 6.

         Option B is not correct.

Option C - (2,2)

          y > –3 x 2 + 3 = -3

         We have y = 2, which is greater than -3.

          y > 2 x 2 – 2  = 2

         We have y = 2, which is not greater than 2.

         Option C is not correct.  

Option D - (0,3)

          y > –3 x 0 + 3 = 3

         We have y = 3, which is not greater than 3.

         Option D is not correct.    

All options are wrong.

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Alex_Xolod [135]

Answer:

A, B, and C

Step-by-step explanation:

If you want to keep a shape congruent, you would only want to change the positioning of said shape.

Dilation is when you change the size of said shape, so it wouldn't work

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Hey guys can any of you guys math geniuses help me out on this math question? 3 3/5 + 1/3=?
Katena32 [7]

Answer:

\dfrac{59}{15}=3 \frac{14}{15}

Step-by-step explanation:

Convert the mixed number into an improper fraction:

3 \frac35=\dfrac{3\times5+3}{5}=\dfrac{18}{5}

Now convert fractions so that their denominators are the same:

\implies \dfrac{18}{5}+\dfrac13=\dfrac{18\times3}{5\times3}+\dfrac{1 \times5}{3 \times 5}=\dfrac{54}{15}+\dfrac{5}{15}

As the denominators are now the same, we can simply add the numerators:

\implies \dfrac{54}{15}+\dfrac{5}{15}= \dfrac{54+5}{15}=\dfrac{59}{15}

Now convert back into a mixed number (if required):

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