Alison is playing a video game. At the end of each level, the player is given either a bag of gold or a magic wand.

Mathematics

1 answer:

Shkiper50 [21]3 years ago

5 0

Outcome Bag of Gold Magic Wand

Relative frequency 0.32 0.68

The relative frequency of getting a bag of gold is .......... reasonably close

.32 is close to 30% so

Alison's claim about the theoretical probability is likely to be 2............true

Further, this means that the theoretical probability of getting a magic wand is most likely 3............1 - 30% = 70%

You might be interested in

Consider the following simplified algebraic expression. Which could be the original expression?

dem82 [27]

You have to simplify each equation. You can do that by adding similar values to each other:

(the first equation)

8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² - 2y² + 3x - 4

To make it easier, arrange the values around so that similar ones are beside each other:

8x²y + 2x²y + 7x² - x² - 5y² - 2y² + 3x + 3x - 2 - 4

then add the similar values together:

8x²y + 2x²y = 10x²y

7x² - x² = 6x²

- 5y² - 2y² = -7y²

3x + 3x = 6x

(- 2)+ (- 4) = -6

and if you put them together:

10x²y + 6x² - 7y² + 6x - 6

This isn't the answer to the equation, because it's different. So repeat the process with all the other equations until you find one that is identical to the simplified version.

The answer is the second one: 8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² - 2y² - 3x - 4

6 0

3 years ago

Read 2 more answers

Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$