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Scorpion4ik [409]
3 years ago
5

It says factor 49x-28

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0
The x is just a variable. It is basically 49-28.
kvasek [131]3 years ago
6 0

Answer:

7(7x-4)

Step-by-step explanation:

We can factor a 7 from each term

49x = 7*7x

28 = 7*4

49x -28

7(7x-4)

You might be interested in
20) -5(1 - 5x) +5(-8x - 2) = -4x – 8x
Alchen [17]

Answer:

x = -5

Step-by-step explanation:

-5(1 - 5x) +5(-8x - 2) = -4x – 8x

First lets simplify each side of the equation.

-5+25x-40x-10 = -4x-8x

Combine like terms

-15x-15=-12x

Add 15x to both sides (addition property of equality)

-15=3x

Divide each side by 3 (division property of equality)

x=-5

The answer is x = -5

5 0
3 years ago
Without using technology, describe the end behavior of f(x) = 3x32 + 8x2 − 22x + 43.
mr Goodwill [35]
F(x) = 3x^32 + 8x^2 -22x +43

The ends of all the polynomials with even degree behave like quadratic functions.

Given the the coefficient of x^32 is positive, the function opens upwards. Then the two ends go up.
8 0
3 years ago
Read 2 more answers
Which system of inequalities does the graph represent?
SSSSS [86.1K]

Answer:system of linear equalities in one variable .

Step-by-step explanation:

3 0
3 years ago
Subtract 0.58 - 0.21. What is the place value of the 7 in the difference? ones tens tenths hundredths
hoa [83]

Answer:

hundredths place



8 0
2 years ago
Read 2 more answers
Solve (x + 5)^(3/2)= (x - 1)^3
IRINA_888 [86]

Answer:

  x = 4

Step-by-step explanation:

For an equation of this sort, my first step is to rewrite it so the solutions are the x-intercepts of the graph:

  (x +5)^(3/2) -(x +1)^3 = 0

The graph is attached. The one real solution is x=4.

__

The solution method for something like this is necessarily ad hoc. Here, it appears that progress can be made by raising both sides of the equation to the 2/3 power:

  ((x +5)^(3/2))^(2/3) = ((x -1)^3)^(2/3)

  x +5 = (x -1)^2

Now, you have an ordinary quadratic that can be solved using any of the usual methods.

  x^2 -2x +1 = x +5 . . . . swap sides, expand the square

  x^2 -3x -4 = 0 . . . . . . put in standard form

  (x -4)(x +1) = 0 . . . . . . factor

The solutions to this are ...

  x = 4, x = -1 . . . . . . . values of x that make the factors zero

__

To see if either of these solutions is extraneous, we can check them:

  (4 +5)^(3/2) = (4 -1)^3 . . . . . substitute 4 for x

  9^(3/2) = 3^3 . . . . . . . . . true

  (-1 +5)^(3/2) = (-1 -1)^3 . . . . . substitute -1 for x

  4^(3/2) = (-2)^3

  8 = -8 . . . . . . . . . . . false; x = -1 is extraneous

The solution is x = 4.

_____

<em>Additional comment</em>

You can eliminate the x=-1 "solution" by considering the domains of the left- and right-side expressions. The 3/2 power is equivalent to the square root of the cube. That will generally only be defined for non-negative values (x ≥ -5). The cube on the right will only be positive for x > 1, so the practical domain of this equation is x ≥ 1.

5 0
2 years ago
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