Answer:
Infinitely many solutions.
Step-by-step explanation:
In the equation −2y + 2y + 3 = 3 we see only one variable, and that variable is of the first power. Ordinarily, we'd say that this equation will have 1 solution. However, if we combine like terms, we get 0 + 3 = 3, or 0 = 0, which is true for any and all y values. Infinitely many solutions.
Answer:
1. Complimentary angles
2. 3x+20 = 10x-15: x = 5
3. I'm not sure on part 3, sorry.
Answer: 118
Explanation:
Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:
61°+61°= 122
180-122=58°
∠DBA=58°
Since triangle BCD is an equilateral triangle, all the interior angles are the same:
180/3=60
∠DBC=60°
∠BCD=60°
∠CDB=60°
Since angles DBC and DBA make up angle ABC, just simply add the two angles together:
58+60=118°
Therefore, ∠ABC is 118°.
We know that imaginary roots always come in pairs, so we already know 4 solutions
-2, 2, 4 + i and a pair of 4 + i
Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots
So for sure, we will have 3 real roots and 2 imaginary roots
Last option, f(x) has three real roots and two imaginary roots
Answer:
7.3% percentage of the bearings produced will not be acceptable.
Step-by-step explanation:
Consider the provided information.
Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.
Let X is the normal random variable which represents the diameter of bearing.
Thus, 0.500-0.004<X<0.500+0.004
0.496<X<0.504
The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.
Use the Z score formula: 
Therefore
Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.
We need to find the percentage of the bearings produced will not be acceptable.
So subtract it from 1 as shown.
1-0.9270=0.073
Hence, 7.3% percentage of the bearings produced will not be acceptable.
