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igomit [66]
3 years ago
14

Solve the inequality x + 2 1/2 > -1/2. Graph the solution set on a number line.show your work.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

x > - 3

Step-by-step explanation:

x + 2\frac{1}{2} > - \frac{1}{2}      First turn 2\frac{1}{2} into an fraction since its easier. So it becomes \frac{5}{2}

x + \frac{5}{2} > - \frac{1}{2}

<u>   - </u>\frac{5}{2}<u>     - </u>\frac{5}{2}<u>  </u>       Do inverse operations, so subtract \frac{5}{2} from both sides.

    x > - \frac{6}{2}          Combine  - \frac{5}{2} with - \frac{1}{2}, which gives us - \frac{6}{2}

    x > - 3          Since we know that 6 divided by 2 is 3.

This would not allow me to attach an image so I am going to type a visual representation f what the graph would look like below)

<-------------O--------------------------------------------------->

-5    -4     -3      -2       -1     0     1     2    3    4     5

So, the number line would be a solid line rather than dashed (but I was not able to attach an image so I kind of had to improvise). When using ≥ ≤ sings the circle of the point is closed. When using < and > signs, the circle of the point is open. Thus, in this scenario since he sign is >, then the circle of the point is open. The direction of the arrow and ray for this equality is going to the right because the answer is that x is greater than - 3, Therefore any values greater than - 3 are a possibility which is why the arrow goes on indefinitely.

 

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dybincka [34]

Answer:

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Step-by-step explanation:

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It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

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$$\begin{aligned}m_{1} &=\frac{5-7}{5-1} \\m_{1} &=\frac{-2}{4} \\m_{1} &=-\frac{1}{2}\end{aligned}$$

Step 2 of 2

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And

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6 0
1 year ago
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9514 1404 393

Answer:

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Step-by-step explanation:

One way to do this is to find the values of g(9) and f(9).

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