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vekshin1
3 years ago
13

How is a net useful when finding the surface area or prisms and pyramids?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer:oh yeah I remember that

Step-by-step explanation:

That’s tuff

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Plz show working for binary addition. please solve. 11000 + 110101 + 101011​​
olga_2 [115]

Answer: The answer to this is 222112

Step-by-step explanation: Its quite simple actually, you add all these numbers together, you bring up any ones that are extras then you add all the ones to the direct answer :> ( Hope this helps!)

4 0
3 years ago
I need EXTREME HELP PLEASE
elena55 [62]

Answer:

8 months

Step-by-step explanation:

194-3m = 217-6m

3m = 23

m=7.666666.....  (8 months

6 0
2 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
Solve for v.<br>2y = 18-41<br>Simplify your answer as much as possible.<br>​
Sloan [31]

Answer:

y = -11.5

Step-by-step explanation:

2y = 18-41

Combine like terms

2y = -23

Divide each side by 2

2y/2 = -23/2

y = -11.5

7 0
3 years ago
The graph shows the relationship between the total cost and the number of erasers bought at the student store. Which statement i
alekssr [168]
Each eraser will cost u 50 cents

so 7 erasers will cost (7 * 0.50) = 3.50 <==
3 0
3 years ago
Read 2 more answers
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