B. y = 10x + 680
<span>Breakdown: </span>
<span>he bring a total of $830 home </span>
<span>he opens 15 accounts at $10/account </span>
<span>he has an unknown amount of salary. </span>
<span>Hence to determine the salary, Subtract the commission of the opened accounts from the total he brings home i.e. </span>
<span>830 = Salary + Commission (rearranging gives) </span>
<span>Salary = 830 - Commission (but Commission = 15*10 = 150) </span>
<span>Salary = 830 - 150 = 680 </span>
<span>Therefore his pay structure is of the form </span>
<span>Y = 680 + 10x, where x is the number of accounts opened </span>
<span>Hope that helps</span>
Well convert all of them into fourths. 3 1/2 = 3 2/4. Add all the whole numbers 2 + 4 + 3 = 9 and then add the fractions 1/4 + 3/4 + 2/4 = 6/4 = 1 2/4. Finally add the whole number and fraction together, 10 2/4 or 10 1/2.
10 1/2 cases of popcorn.
Answer: 30.85%.
Step-by-step explanation:
Let X denotes the score of random student.
Given: 
and 
We assume that scores are normally distributed.
Then , the probability that a a student score higher than 55:
![P(X>55)=P(\dfrac{X-\mu}{\sigma}>\dfrac{55-50}{10})\\\\=P(Z>0.5) \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E55%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B55-50%7D%7B10%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.5%29%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.5%29%5C%5C%5C%5C%3D1-0.6915%5C%20%5B%5Ctext%7BBy%20p-value%20table%20for%20z%7D%5D%5C%5C%5C%5C%3D%200.3085)
Hence, the percent of students have a higher score than hers is 30.85%.
Answer:
a. 35
b. 13
Step-by-step explanation:
a. x/5= 7
Cross Multiplication
x= (7)(5)
x= 35
b. x/2= 6.5
Cross Multiplication
x=(6.5)(2)
x=13
Answer: Z> -17
z/2+26=17.5
We move all terms containing z to the left and all other terms to the right.
+ 0.5z=+17.5-26
We simplify left and right side of the equation.
+ 0.5z=-8.5
We divide both sides of the equation by 0.5 to get z.
z=-17
