You distribute the -4 with the -8x and -8 which results in 32x+32.
Complete question is;
A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer:
Price to maximize revenue = $100
Maximum revenue = $25000
Step-by-step explanation:
We are told that:
R = -2.5p² + 500p, where p is the price in dollars of the software.
The maximum revenue will occur at the vertex of the parabola.
Thus, the price at this vertex is;
p = -b/2a
Where a = - 2.5 and b = 500
Thus:
p = -500/(2 × -2.5)
p = -500/-5
p = 100 in dollars
Maximum revenue at this price is;
R(100) = -2.5(100)² + 500(100)
R(100) = -25000 + 50000
R(100) = $25000
16-7 is 9, so basically you could do, and these are not the only ones you can do..
100-91
10-1
15-6
20-11
Answer:
A) 37:191
B)191:154
Step-by-step explanation:\
A) Mary's Savings= 185 Rs
Mary's Income= 955 Rs
Ratio = 185:955
= 185/955
=37/191 ( INTO LOWEST TERMS )
=37:191
B) Mary's Income= 955 Rs
Mary's Expenditure= ?? = Income- Saving = 955-185= 770
Ratio= 955:770
= 955/770
= 191/154 ( INTO LOWEST TERMS )
= 191:154
