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Sveta_85 [38]
3 years ago
12

Which of the following is a biotic component that would help determine the health of an ecosystem

Biology
1 answer:
Elden [556K]3 years ago
7 0

Answer:plants

Explanation:the greener and more vegetated ecosystem is more healthier with plenty of habitat,food and moisture provided for other living organisms and also attracting agents like pollinators .

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when the atmosphere changes due to the human activities, how does the change affect humans in return?
Valentin [98]

Answer:

Climate change effects such as hunger, poverty and diseases like diarrhea and malaria, disproportionately impact children; about 90 percent of malaria and diarrhea deaths are among young children. Children are also 14–44 percent more likely to die from environmental factors, again leaving them the most vulnerable.

Explanation:

여기 당신의 대답이 있습니다 당신이 즐기고 나를 브레인리스트로 표시하기를 바랍니다 감사하다

6 0
2 years ago
Read 2 more answers
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
Why is it important that an expeirement include a control group​
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Without a control group there wouldn’t be any basis for knowing if a result is due to the variable being tested
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3 years ago
The North Atlantic right whale migrates between subtropical and polar waters annually. Nearly 50 percent of right whale deaths a
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Sonar testing has caused whales to die in mass amounts.
8 0
1 year ago
Never mind i dont need help
Leno4ka [110]

Answer:

okay buddy, have fun with that.

Explanation:

thanks

6 0
3 years ago
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