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2 years ago

If MN = 3 and MN = AB, then AB = 3. This is an illustration of which property?

Mathematics

1 answer:

vova2212 [387]2 years ago

8 0

<span>If MN = 3 and MN = AB, then AB = 3
</span>answer
Transitive Property

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Camden is working two summer jobs, making $10 per hour babysitting and making $18 per hour lifeguarding. In a given week, he can

nirvana33 [79]

Answer:

2 hours babysitting

Step-by-step explanation:

First you would multiply 14 by 9 and you would get 162

Then you would Subtract 180 by 162 and you would get 18

So than you would keep on multiplying 10 till you get 20 which would be 2

So therefore your answer would be 2

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2 years ago

ming- LI spent $15 at the movies. She then earned $30 babysitting. She spent $12 at the bookstore. She ow has $18 left. How much

valentina_108 [34]

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$29

Step-by-step explanation:

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3 years ago

What's the ordered pair ?

nekit [7.7K]

The answer will be the set of points that contains a different x value for each point.

We clearly see that for ever point in terms of CHOICE C the value of x is different.

Answer: Choice C

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3 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

Elias and Mark together have $756.80. Elias has $489.50. Write and solve an addition equation to determine how much money Mark (

Degger [83]

Answer:

489.5 + m = 756.80 (the amount elias has, added to marks is equal to the total

(756.8- 489.5 = 267.30 which is the amount mark has.)

m= 267.3

the last option is the correct option

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers