It mean that everything is goin down and that there isnt anything interfering with it
Answer:
$1699.25
Step-by-step explanation:
Data:
Cost = $314 000
Down payment = 18 %
Term = 20 yr
i = 5 %/yr
Calculations:
(a) <em>Down payment
</em>
Down payment = 314 000 × 0.18
= $56 520
(b) <em>Amount financed
</em>
Cost = $314 000
-Down payment = <u> 56 520</u>
Financed = $257 480
(c) <em>Monthly payments </em><em>
</em>
The formula for the monthly payment (P) on a loan of A dollars that is paid back in equal monthly payments over n months, at an annual interest rate of i % is

We must express the interest rate on a monthly basis.
I = 5 %/yr = 0.41 667 %/mo = 0.004 1667
n = 2 × 12 = 240 mo




P = $1699.25
Carlos' monthly mortgage payment will be $1699.25.
Answer:

Step-by-step explanation:
We are given that:

Where θ is in QIV.
And we want to find the value of tan(θ).
Recall that cosine is the ratio of the adjacent side over the hypotenuse.
Therefore, the opposite side is:

Next, in QIV, only cosine is positive: sine and tangent are both negative.
Tangent is the ratio of the opposite side to the adjacent. So:

Substitute. Tangent is negative in QIV. Hence:

Answer:
Q1:=
Q2:4x+2
I believe question 3 is MN 2
3^3
33 + 87 + x = 180
120 + x = 180
x = 60
y + x = 180
y + 60 = 180
y = 120