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alexdok [17]
3 years ago
6

What is the least common denominator of these fractions? 1/2x - 5/4 + 2x = 5/6 + x

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

12

Step-by-step explanation:

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It’s solution in step by step explanation pls help
Pavel [41]

Answer:

6) x^2 -4x+1

7)   26x-1y +4z

Step-by-step explanation:

long division

       

      ____x^{2}__-4x__+1____

x-2 | x^3-6x^2+9x-2

  -    x^3-2x^2<u />

       -----------

             -4x^2+9x

             -4x^2+8x

        ----------------

                x-2

                x-2  

4 0
3 years ago
si en una fraccion uno de los terminos es un numero primo, ¿se puede asegurar que es irreducible? ¿por que?
weeeeeb [17]

Answer:

“yes, but terms and conditions apply.” · Since no (non-trivial) fraction is a natural number, obviously no fraction.

i think

Step-by-step explanation:

5 0
3 years ago
22.857142857142858 As a fraction
Mamont248 [21]

Answer:

Step-by-step explanation:

1. The answer is 8/35.

2. This works because 8/35 equals 22.857142857142858.

Please give me brainliest, I really need it! Thank you!

5 0
1 year ago
Stephen is making a map of his neighborhood. He knows the following info: the distance from his home to the park is 10 blocks th
SpyIntel [72]
An architect plans to make a drawing of the room of a house. The segment LM represents the ceiling of the room. He wants to construct a line passing through Q and perpendicular to side LM to represent a wall of the room. He uses a straightedge and compass to complete some steps of the construction, as shown below:
4 0
3 years ago
How do I Factor 125x^3 -64<br><br> The answer is not (5x+4)(5x-4) or (5x-4)(25x^2 +15x+16)
pychu [463]

The correct factorization would be (5x - 4)(25x^2 + 20x + 16).

The law of factoring cubes states that we use the following formula when we have two cubes being subtracted by one another.

(a - b)(a^2 + ab + b^2)

If we take the cube root of 125x^3 we get 5x, which will be our a value. If we take the cube root of 64, we get 4, which will be our b value. Then we plug in to the formula.

(5x - 4)((5x)^2 + (5x)(4) + 4^2)

(5x - 4)(25x^2 + 20x + 16)

I think the problem with your second answer is that you just did not properly multiply the 5x and the 4 to get 20x (instead you got 15x).

8 0
3 years ago
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