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stealth61 [152]
3 years ago
6

a business analyst makes 20$ an hour for the first 42 hours he works during a week and 28$ an hour for each worked over 42 hours

. which piecewise equation models his weekly pay y in dollars as it relates to the number of hours x that he has worked during the week
Mathematics
2 answers:
sashaice [31]3 years ago
8 0
Y=(20 × 42) + [28 × (x-42)]
7nadin3 [17]3 years ago
6 0

Answer:

y=28(x-42)+840

Step-by-step explanation:

Let he works for x hours in total.

We are given that he makes 20$ an hour for the first 42 hours

So, he earns in 1 hour = 20

He earns in 42 hours = 20 \times42

                                   = 840

Now we are given that he earns $28 an hour for each hour worked over 42 hours.

Since he worked for 42 hours out of x hours .

So, remaining hours = x-42 hours

So,he earns for x-42 hours = 28\times(x-42)

y denotes his total earning of weekly

So, total earning y=28(x-42)+840

Hence piecewise equation models his weekly pay y in dollars as it relates to the number of hours x that he has worked during the week is y=28(x-42)+840                                

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3 0
3 years ago
Read 2 more answers
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

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5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

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6 0
3 years ago
Read 2 more answers
A man standing on level ground is 1000 feet away from the base of a 350-foot-tall building. Find,
CaHeK987 [17]

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