All categories

2 years ago

8=3a-4 please help quickly plssssssss

Mathematics

2 answers:

serg [7]2 years ago

6 0

Answer: a=4

Step-by-step explanation:

Bad White [126]2 years ago

3 0

Answer:

a = 4

Step-by-step explanation:

You might be interested in

(x + 2)(x2 + 5x + + 1)

butalik [34]

Answer:

${x}^{3} + 7 {x}^{2} + 11x + 2$

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

6 0

3 years ago

What is the width of a rectangle with length 14cm and area 161 cm^2

Inessa05 [86]

Answer:

Step-by-step explanation:

The area of a rectangle can be found with the formula $A = l*w$ , where $l$ is the length of the rectangle and $w$ is the width.

From the given problem statement, we know that $l = 14$ and $A = 161$ , so we can fill in those values in the formula anbd solve for $w$ to get the width:

$A = l*w$

$161 = 14w$

Divide both sides by $14$ to isolate $w$ by itself:

$\frac{161}{14} = \frac{14w}{14}$

$w = 11.5$

3 0

2 years ago

Read 2 more answers

I need help with #65 to #70 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP… it is

never [62]

All of the given questions(#65 to #70) are AP(s).

Formula to be used: a(n) = a(1) + (n - 1)d

Pronounced as:

nth term = 1st term + (n - 1)d, where d is the common difference.

*d = difference of any two consecutive terms.

65):

1st term = 2, d = 6 - 2 = 4

Therefore,

11th term = 2 + (11 - 1)4 = 42

66):

1st term = 5, d = 15 - 5 = 10

Therefore,

16th term = 5 + (16 - 1)10 = 155

67):

1st term = 19, d = 39 - 19 = 20

Therefore,

21st term = 19 + (21 - 1)20 = 419

68):

1st term = 8, d = 38 - 8 = 30

Therefore,

36th term = 8 + (36 - 1)30 = 1058

69):

1st term = 1/2, d = 1 - 1/2 = 1/2

Therefore,

101st term = 1/2 + (101 - 1)1/2 = 101/2

70):

1st term = 0.75, d = 1.50 - 0.75 = 0.75

Therefore,

151st term = 0.75 + (151 - 1)(0.75) = 113.25

8 0

2 years ago

Solve the absolute value inequality: |x + 12| + 5 < 27 Isolate the absolute value by subtracting 5 from both sides.

Feliz [49]

Answer:

- 34 < x < 10

Step-by-step explanation:

Inequalities of the type | x | < a, always have a solution of the form

- a < x < a

given | x + 12 | + 5 < 27 ( subtract 5 from both sides )

| x + 12 | < 22, then

- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )

- 34 < x < 10

8 0

3 years ago

Read 2 more answers

Which graph of y=log(-x)?

Leno4ka [110]

Answer: The graph is attached. Please note that the logarithm function is defined for non-negative Reals only. Therefore the log(-x) only exists in the negative interval (-inf,0). Please let me know if you have any questions.

7 0

3 years ago

Read 2 more answers