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Tems11 [23]
3 years ago
15

Use the above figure to answer the question. What's the angle between the tangents at T in the figure?

Mathematics
2 answers:
Gnoma [55]3 years ago
4 0

I believe that the answer is B) 60°.

Because the angle inside the circle equals 120°, and since these are 30°, 60°, 90° triangles, angles A and B are both 90°.

Which means that the remaining angles outside the circle each equal 30°.

Therefore, when both of these angles are added together, ∠T = 60°

Phantasy [73]3 years ago
4 0

Answer: 60 degrees (choice B)

=============================================

Explanation:

Triangle OTA is a 30-60-90 right triangle. This means that the three angles are 30 degrees, 60 degrees, 90 degrees for angles T, O and A in that order. We know that angle A is 90 degrees because the tangent segment AT is perpendicular to the radius at the point of tangency. This leaves angle T to be 30 degrees. Note how the three angles (30,60,90) add up to 180 degrees. Put another way: angle T and angle O are complementary angles, so they must add to 90 degrees.

Triangle OTB is a mirror reflection of triangle OTA. We can prove this using the hyponteuse leg (HL) congruence theorem. Specifically, OA = OB is the congruent pair of legs and OT = OT is the congruent pair of hypotenuses.

Because of this triangle congruence, all of the corresponding angles are congruent as well.

Check out the attached image below.

At this point, we simply add angle OTA and angle OTB to get the answer we want: 30+30 = 60. The angle ATB is the angle between the two tangents segment AT and segment BT.

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

x_{2} = t_{2}

x_{3} = t_{3}

x_{4}  = t_{4}

x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

where,

t_{i} \geq 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

                                                      = _{4}^{24}\textrm{C}

                                                      = 10626

Answer :

no. of solutions for the eqn 10626

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<h3>Indices </h3>

From the question, we are to determine what the four powers have in common

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Hence, the four powers have zero (0) in common.

Learn more on Indices here: brainly.com/question/15361818

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Answer:

Step-by-step explanation:

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