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vivado [14]
3 years ago
6

Et one factory the ratio of defective bulbs produced to the total light bulbs produced is 3:500. How many light bulbs are expect

ed to be defective when 12,000 are produced?
Mathematics
1 answer:
In-s [12.5K]3 years ago
8 0

The answer is:

3 : 500 = x : 12000

x = (3*12000)/500

x = 36000/500

x = 72

72 light bulbs are expected to be defective when 12000 are produced.

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Serhud [2]

Answer:

Equilateral Triangle

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3 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
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patriot [66]
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3 years ago
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attashe74 [19]

1048576 is the answer :)

7 0
3 years ago
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Vinvika [58]
The slope-intercept is y = mx+b. You can use this as a technique for graphing to make the experience easier. The "5" would be the slope or rise/run of the line. The 10 would be where it started on the y-intercept. You could also say it would be (0,10). Since the slope is positive than it would be going in an upward direction. That is why this technique is good for graphing. I hope this helps you and please put me as the brainliest answer. :)
5 0
3 years ago
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