All categories

3 years ago

What is 3 times piy time 53 divided by 72

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Answer:

6.93768377668

Step-by-step explanation:

confusion

You might be interested in

Halp meh ;w; Also hope everyones have a good day

Alex17521 [72]

10/3 goes where 3 and 1/3 is.

This is because 10/3 as a mixed number is 3 and 1/3.

17/3 is where 5 and 2/3 is. Do the same thing as before.

Hope this helps!

7 0

4 years ago

Read 2 more answers

#6 is the question, are these two functions inverse’s

olya-2409 [2.1K]

I will find the inverse function of f(n) to see if it is g(n).

$f(n) = 2(n - 2)^3$

$y = 2(x - 2)^3$

$x = 2(y - 2)^3$

$(y - 2)^3 = \dfrac{x}{2}$

$y - 2 = \sqrt[3]{\dfrac{x}{2}}$

$y = \sqrt[3]{\dfrac{x}{2}} + 2$

$y = \sqrt[3]{ \dfrac{x}{2} } \times \sqrt[3]{ \dfrac{4}{4}} + 2$

$y = \sqrt[3]{\dfrac{4x}{8}} + 2$

$y = \dfrac{ \sqrt[3]{4x }}{2} + 2$

$g(n) = \dfrac{\sqrt[3]{4n}} {2} + 2$

The inverse function of f(n) is indeed g(n), so f(n) and g(n) are inverse functions.

8 0

3 years ago

Open Response Factor 12m + 5n. Explain<br> how you found your answer. (Lesson 4)

Brilliant_brown [7]

Answer:

how are u hottie here's my pfp

Step-by-step explanation:

4 0

2 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

With a Explanation “for understanding”

Genrish500 [490]

Answer:

b is less than or equal to -6

Step-by-step explanation:

1. Multiply both sides by -1

2. Simplify

3. Divide both sides by 13

6 0

3 years ago

Read 2 more answers