The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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C
5 x f
5 = price for flowers
f = variable = how many flowers.
Answer:✓ 819/13= 63 miles distance in one hour 8*(63)=504 miles in 8 hours Warning: I am sick in bed. Double check my work.
Step-by-step explanation:
X= my age
500-3x=230
500-3x-230=230-230
270-3x=0
270-3x+3x=0+3x
270=3x
270/3=3x/3
x=90
you are 90 years old
The greatest common factor of this can be solved by looking at the individual parts and splitting it up.
First, we have 28 and 7. Well, thats an easy one. 7 goes into 28 4 times so we are now left with 4 and 1.
We can also write the rest of this like this 4(x*x*y) - 1(x*y*y*y*y*y)
Now, what values are in both equations. We have one x and one y that can be taken out of both.
We end up with 7xy(4x-7y^4)
