The function f(x)=(2/5)x is shown on the coordinate plane.

1 answer:

5 0

None of these answer choices are correct. As X decreases f of x decreases without bound as X increases f of x increases without bound look to be sure you copied the question right

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A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w

sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0

3 years ago

Solve for z<br><br>-p(d+z)=-2z+59

suter [353]

Distribute
-pd-pz=-2z+59
add 2z both sides
-pd-pz+2z=59
add pd to both sides
-pz+2z=59+pd
2z-pz=59+pd
undistribute z
z(2-p)=59-pd
divide bot sides by 2-p
$z=\frac{59-pd}{2-p}$
$z=\frac{pd-59}{p-2}$