What is the additive inverse of -4a

1 answer:

3 0

The additive inverse of something is the number that, if you add it to the original number, you get 0.

The additive inverse of 5, for example, is -5. 5 plus -5 = 0.

You should be able to see how additive inverses are always going to be just the original number with the signs changed. (i.e., times -1)

The additive inverse of -4a would be 4a. -4a + 4a = 0.

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how do you rewrite : y=x^2-5x+9 in standard form using complying the square? I keep getting to : x^2-5x-25/4 but I’m not allowed

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I presume with this you meant to say you want this equation in general form, also known as vertex form, which is y = a(x - h)² + k, instead of standard form, which is y = ax² + bx + c, which is what the original equation is already in.

So with completing the square, you first have to isolate the x-terms. To do this, subtract 9 on both sides of the equation:

$y-9=x^2-5x$

Next, we want to make the right side of the equation a perfect square. To find the constant of this soon-to-be perfect square, divide the x-coefficient by 2 and square that quotient. In this case:

$-5\div 2 = -\frac{5}{2}\\\\(-\frac{5}{2})^2=-\frac{5}{2}\times-\frac{5}{2}=\frac{25}{4}$

Now add 25/4 on both sides of the equation:

$y-9+\frac{25}{4}=x^2-5x+\frac{25}{4}$

Now to combine -9/1 and 25/4, they must have the same denominator, and to find it you must find the LCD, or lowest common denominator, of 1 and 4. To find it, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 4. Multiply both sides of -9/1 by 4/4 and then add the numerators up:

$-\frac{9}{1}\times \frac{4}{4}=-\frac{36}{4}\\\\-\frac{36}{4}+\frac{25}{4}=-\frac{11}{4}\\\\y-\frac{11}{4}=x^2-5x+\frac{25}{4}$